![]() Original link is here:ÄP solution O(n²) 1380ms class Solution: def minRefuelStops(self, target: int, startFuel: int, s: List]) -> int: dp = + * len(s) for i in range(len(s)): for t in range(i + 1): if dp >= s: dp = max(dp, dp + s) for t, d in enumerate(dp): if d >= target: return t return -1ÄP solution with priority queue O(nlogn) 120 ms import heapq class Solution: def minRefuelStops(self, target: int, cur: int, s: List]) -> int: pq = res = i = 0 while cur = Pįor each pair (p, g) of (profit, group), I update the count in dp. Improved DP rocks with complexity of O(N²). class Solution: def minRefuelStops(self, target: int, startFuel: int, stations: List]) -> int: if not stations: if target>startFuel:return -1 else: return 0 stations.append() def dfs(): res = float('inf') open_list = while open_list: i, f, d,dis = open_list.pop() if dis=target: if d=0: if d+1Nylon Color : as the picture shown Size: thick : 0.7mm width: 20mm,25mm,32mm,38mm,50mm Use For: Knapsack Tape DIY Bag Strap Sewing Belt Accessories Package: 8Meters Notice: 1. Solution of 0â1 Knapsack problem with O(NW) complexity can be found on the following slides p35. Webbing with fine weave pattern is easy to sew with to create (diy) slings, ladders, dog leash, guitar strap, box straps, etc. The improved one has the complexity of O(NW) The naive 0â1 Knapsack problem has the complexity of O(2^n) as for each item we have two options. ![]() ![]() Lot of DP problems has some similarity to 0â1 Knapsack problem. ![]()
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